What is the derivative of 7(2xe^x+e^xx^2) ?

The derivative of 7(2xe^x+e^xx^2) is 7(e^xx^2+4e^xx+2e^x)

What is the first derivative of 7(2xe^x+e^xx^2) ?

The first derivative of 7(2xe^x+e^xx^2) is 7(e^xx^2+4e^xx+2e^x)

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\frac{d}{d x} (7 (2 x e^{x} + e^{x} x^{2}))

7 (e^{x} x^{2} + 4 e^{x} x + 2 e^{x})

Solution steps

\frac{d}{d x} (7 (2 x e^{x} + e^{x} x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (2 x e^{x} + e^{x} x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 7 (\frac{d}{d x} (2 x e^{x}) + \frac{d}{d x} (e^{x} x^{2}))

\frac{d}{d x} (2 x e^{x}) = 2 (e^{x} + e^{x} x)

\frac{d}{d x} (e^{x} x^{2}) = e^{x} x^{2} + 2 x e^{x}

= 7 (2 (e^{x} + e^{x} x) + e^{x} x^{2} + 2 x e^{x})

Expand

2 (e^{x} + e^{x} x) + e^{x} x^{2} + 2 x e^{x} : e^{x} x^{2} + 4 e^{x} x + 2 e^{x}

= 7 (e^{x} x^{2} + 4 e^{x} x + 2 e^{x})

\int y + x e^{y} d y

x \to \infty lim (1 \cdot x)

\frac{d}{d x} (\frac{x ^{3} - 8}{x ^{3} + 8})

\frac{\partial}{\partial x} (x^{2} y - y^{2} - 7)

\int sec^{5} (4 x) tan (4 x) d x

What is the derivative of 7(2xe^x+e^xx^2) ?
The derivative of 7(2xe^x+e^xx^2) is 7(e^xx^2+4e^xx+2e^x)
What is the first derivative of 7(2xe^x+e^xx^2) ?
The first derivative of 7(2xe^x+e^xx^2) is 7(e^xx^2+4e^xx+2e^x)