What is inverse oflaplace 2/((s^2+4)) ?

The answer to inverse oflaplace 2/((s^2+4)) is sin(2t)

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inverse oflaplace 2/((s^2+4))

inverse laplace

\frac{2}{( s ^{2} + 4 )}

sin (2 t)

Solution steps

L^{- 1} {\frac{2}{( s ^{2} + 4 )}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s ^{2} + a ^{2}}} = sin (a t)

L^{- 1} {\frac{2}{s ^{2} + 2 ^{2}}} = sin (2 t)

= sin (2 t)

y = x, y = 2 x 1 - x^{2}

\frac{d}{d x} (e^{x} sin (x^{2}))

\frac{d}{d x} (2 x + sin (2 x))

\frac{\partial}{\partial y} (x e^{7 x y})

\int e^{(x - 1)} d x

What is inverse oflaplace 2/((s^2+4)) ?
The answer to inverse oflaplace 2/((s^2+4)) is sin(2t)