What is the limit as t approaches 0+of (sin(t))/t ?

The limit as t approaches 0+of (sin(t))/t is 1

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limit as t approaches 0+of (sin(t))/t

t \to 0 + lim (\frac{sin ( t )}{t})

1

Solution steps

t \to 0 + lim (\frac{sin ( t )}{t})

Apply L'Hopital's Rule

: t \to 0 + lim (\frac{cos ( t )}{1})

= t \to 0 + lim (\frac{cos ( t )}{1})

Plug in the value

t = 0

= \frac{cos ( 0 )}{1}

Simplify

\frac{cos ( 0 )}{1} : 1

= 1

\frac{d}{d x} (x^{3} (4 - x^{2}))

\frac{d}{d x} (\frac{x ^{2}}{2} + 1)

n = 0 \sum \infty \frac{e}{n}

\frac{\partial}{\partial x} (ln (t^{2} + 1))

\frac{d}{d x} (a x^{5} ln (\frac{x}{2}) + b x^{3} (x - 2))

What is the limit as t approaches 0+of (sin(t))/t ?
The limit as t approaches 0+of (sin(t))/t is 1