What is the derivative of tan(x^3+1) ?

The derivative of tan(x^3+1) is sec^2(x^3+1)*3x^2

What is the first derivative of tan(x^3+1) ?

The first derivative of tan(x^3+1) is sec^2(x^3+1)*3x^2

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\frac{d}{d x} (tan (x^{3} + 1))

sec^{2} (x^{3} + 1) \cdot 3 x^{2}

Solution steps

\frac{d}{d x} (tan (x^{3} + 1))

Apply the chain rule:

sec^{2} (x^{3} + 1) \frac{d}{d x} (x^{3} + 1)

= sec^{2} (x^{3} + 1) \frac{d}{d x} (x^{3} + 1)

\frac{d}{d x} (x^{3} + 1) = 3 x^{2}

= sec^{2} (x^{3} + 1) \cdot 3 x^{2}

\int_{2}^{3} t^{2} d t

f (x) = (- x^{2} + 3)^{2}

f (x) = (x + 2) (2 x^{2} - 3)

arcsin (x), 0

\int (6 x^{2}) (e^{x^{3} + 2}) d x

What is the derivative of tan(x^3+1) ?
The derivative of tan(x^3+1) is sec^2(x^3+1)*3x^2
What is the first derivative of tan(x^3+1) ?
The first derivative of tan(x^3+1) is sec^2(x^3+1)*3x^2