What is the derivative of y=4+sqrt(x) ?

The derivative of y=4+sqrt(x) is 1/(2sqrt(x))

What is the first derivative of y=4+sqrt(x) ?

The first derivative of y=4+sqrt(x) is 1/(2sqrt(x))

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derivative of

y = 4 + x

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (4 + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) + \frac{d}{d x} (x)

\frac{d}{d x} (4) = 0

\frac{d}{d x} (x) = \frac{1}{2 x}

= 0 + \frac{1}{2 x}

Simplify

= \frac{1}{2 x}

\frac{d ^{2} y}{d x ^{2}} + 8 \frac{d y}{d x} + 16 y = 0

cos (π x), 0

\frac{16}{x}

\frac{\partial}{\partial y} (3 x^{2})

\frac{d}{d x} (x^{5} - 5 x)

What is the derivative of y=4+sqrt(x) ?
The derivative of y=4+sqrt(x) is 1/(2sqrt(x))
What is the first derivative of y=4+sqrt(x) ?
The first derivative of y=4+sqrt(x) is 1/(2sqrt(x))