en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(t)=ln(t+1)

Solution

f (t) = ln (t + 1)

Solution

Domain : t > - 1

Range : - \infty < f (t) < \infty

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical t = - 1

Extreme Points : None

+1

Interval Notation

Domain : (- 1, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

ln (t + 1) : t > - 1

Range of

ln (t + 1) : - \infty < f (t) < \infty

Axis interception points of

ln (t + 1) :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

ln (t + 1) :

Vertical

: t = - 1

Extreme Points of

ln (t + 1) :

None

Popular Examples

derivative of x^2+3x+sqrt(4)

\frac{d}{d x} (x^{2} + 3 x + 4)

t*(dy)/(dt)+37y= 1/t

t \cdot \frac{d y}{d t} + 37 y = \frac{1}{t}

slope of x^2-1 slope

x^{2} - 1

integral of 1/(y-4)

\int \frac{1}{y - 4} d y

4y^{''}-40y^'+96y=5sin(2x)

4 y^{^{''}} - 40 y^{^{'}} + 96 y = 5 sin (2 x)

Frequently Asked Questions (FAQ)

What is the f(t)=ln(t+1) ?
The f(t)=ln(t+1) is