What is the integral from-9 to-8 of 1/x ?

The integral from-9 to-8 of 1/x is 3ln(2)-2ln(3)

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integral from-9 to-8 of 1/x

\int_{- 9}^{- 8} \frac{1}{x} d x

3 ln (2) - 2 ln (3)

Decimal Notation

- 0.11778 \dots

Solution steps

\int_{- 9}^{- 8} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{- 9}^{- 8}

Compute the boundaries:

3 ln (2) - 2 ln (3)

= 3 ln (2) - 2 ln (3)

\int 9 sin (4 x) cos (2 x) d x

x^{^{'''}} + x = 0

y^{^{'}} = - sin (π x)

\frac{d}{d x} (ln (- 3 x + 2))

\int_{0}^{- 0.4} 150 x d x

What is the integral from-9 to-8 of 1/x ?
The integral from-9 to-8 of 1/x is 3ln(2)-2ln(3)