What is (\partial}{\partial s}(\frac{s-2r)/t) ?

The answer to (\partial}{\partial s}(\frac{s-2r)/t) is 1/t

Popular >

(\partial}{\partial s}(\frac{s-2r)/t)

\frac{\partial}{\partial s} (\frac{s - 2 r}{t})

\frac{1}{t}

Solution steps

\frac{\partial}{\partial s} (\frac{s - 2 r}{t})

Treat

r, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{t} \frac{\partial}{\partial s} (s - 2 r)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{t} (\frac{\partial}{\partial s} (s) - \frac{\partial}{\partial s} (2 r))

\frac{\partial}{\partial s} (s) = 1

\frac{\partial}{\partial s} (2 r) = 0

= \frac{1}{t} (1 - 0)

Simplify

= \frac{1}{t}

\int \frac{3 x + 1}{x} d x

y^{^{''}} - 8 y^{^{'}} + 16 y = 0, y (0) = 3, y^{^{'}} (0) = 0

\frac{d}{d x} (2 x^{2} + 7)

f (x) = (4 x + 5) (5 x - 1), at x = 3

\int 25 e^{- 5 x} sin (5 x) d x

What is (\partial}{\partial s}(\frac{s-2r)/t) ?
The answer to (\partial}{\partial s}(\frac{s-2r)/t) is 1/t