What is the integral of xsin(ln(x)) ?

The integral of xsin(ln(x)) is -1/5 x^2cos(ln(x))+2/5 x^2sin(ln(x))+C

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integral of xsin(ln(x))

\int x sin (ln (x)) d x

- \frac{1}{5} x^{2} cos (ln (x)) + \frac{2}{5} x^{2} sin (ln (x)) + C

Solution steps

\int x sin (ln (x)) d x

Apply u-substitution

: \int e^{2 u} sin (u) d u

= \int e^{2 u} sin (u) d u

Apply Integration By Parts

: - e^{2 u} cos (u) - \int - 2 e^{2 u} cos (u) d u

= - e^{2 u} cos (u) - \int - 2 e^{2 u} cos (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{2 u} cos (u) - (- 2 \cdot \int e^{2 u} cos (u) d u)

Apply Integration By Parts

: e^{2 u} sin (u) - \int e^{2 u} \cdot 2 sin (u) d u

= - e^{2 u} cos (u) - (- 2 (e^{2 u} sin (u) - \int e^{2 u} \cdot 2 sin (u) d u))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{2 u} cos (u) - (- 2 (e^{2 u} sin (u) - 2 \cdot \int e^{2 u} sin (u) d u))

Therefore

\int e^{2 u} sin (u) d u = - e^{2 u} cos (u) - (- 2 (e^{2 u} sin (u) - 2 \cdot \int e^{2 u} sin (u) d u))

Isolate

\int e^{2 u} sin (u) d u

= - \frac{e ^{2 u} cos ( u )}{5} + \frac{2 e ^{2 u} sin ( u )}{5}

Substitute back

u = ln (x)

= - \frac{e ^{2 l n (x)} cos ( ln ( x ) )}{5} + \frac{2 e ^{2 l n (x)} sin ( ln ( x ) )}{5}

Simplify

- \frac{e ^{2 l n (x)} cos ( ln ( x ) )}{5} + \frac{2 e ^{2 l n (x)} sin ( ln ( x ) )}{5} : - \frac{1}{5} x^{2} cos (ln (x)) + \frac{2}{5} x^{2} sin (ln (x))

= - \frac{1}{5} x^{2} cos (ln (x)) + \frac{2}{5} x^{2} sin (ln (x))

Add a constant to the solution

= - \frac{1}{5} x^{2} cos (ln (x)) + \frac{2}{5} x^{2} sin (ln (x)) + C

\int_{4}^{\infty} e^{- \frac{x}{2}} d x

\int \frac{ln ( x ) + 10}{x} d x

5 - x^{2}

\int_{- 2}^{2} \frac{1}{v} d v

x \to 0 + lim (x^{5 x})

What is the integral of xsin(ln(x)) ?
The integral of xsin(ln(x)) is -1/5 x^2cos(ln(x))+2/5 x^2sin(ln(x))+C