What is inverse oflaplace 2/((s-4)^3) ?

The answer to inverse oflaplace 2/((s-4)^3) is e^{4t}t^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace 2/((s-4)^3)

inverse laplace

\frac{2}{( s - 4 ) ^{3}}

e^{4 t} t^{2}

Solution steps

L^{- 1} {\frac{2}{( s - 4 ) ^{3}}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {F (s - a)} = e^{a t} f (t)

For

\frac{2}{( s - 4 ) ^{3}} : a = 4, F (s) = \frac{2}{s ^{3}}

= e^{4 t} L^{- 1} {\frac{2}{s ^{3}}}

L^{- 1} {\frac{2}{s ^{3}}} : t^{2}

= e^{4 t} t^{2}

\int_{- π}^{π} sin (k x) cos (n x) d x

x^{^{'}} = a x - b x^{2}

x \to - 1 lim (\frac{f ( x )}{x + 1})

y^{^{'}} = \frac{- x y ^{2}}{2}

\int \frac{1}{N} d N

What is inverse oflaplace 2/((s-4)^3) ?
The answer to inverse oflaplace 2/((s-4)^3) is e^{4t}t^2