What is the derivative of x^3-y^3 ?

The derivative of x^3-y^3 is 3x^2-3y^2(dy)/(dx)

What is the first derivative of x^3-y^3 ?

The first derivative of x^3-y^3 is 3x^2-3y^2(dy)/(dx)

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\frac{d}{d x} (x^{3} - y^{3})

3 x^{2} - 3 y^{2} \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{3} - y^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (y^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (y^{3}) = 3 y^{2} \frac{d y}{d x}

= 3 x^{2} - 3 y^{2} \frac{d y}{d x}

\frac{d}{d x} (\frac{2}{9 x ^{\frac{5}{3}}})

y^{2} = x + 6, y^{2} = 2 - x

\frac{d}{d x} (4 cos (3 x))

\int_{1}^{2} tan (x y) d y

\frac{d}{d x} (8 x^{4} + 5 x^{3} - x^{2} + 4 x - 1)

What is the derivative of x^3-y^3 ?
The derivative of x^3-y^3 is 3x^2-3y^2(dy)/(dx)
What is the first derivative of x^3-y^3 ?
The first derivative of x^3-y^3 is 3x^2-3y^2(dy)/(dx)