What is the derivative of 2/(9x^{5/3}) ?

The derivative of 2/(9x^{5/3}) is -(10)/(27x^{8/3)}

What is the first derivative of 2/(9x^{5/3}) ?

The first derivative of 2/(9x^{5/3}) is -(10)/(27x^{8/3)}

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\frac{d}{d x} (\frac{2}{9 x ^{\frac{5}{3}}})

- \frac{10}{27 x ^{\frac{8}{3}}}

Solution steps

\frac{d}{d x} (\frac{2}{9 x ^{\frac{5}{3}}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{9} \frac{d}{d x} (\frac{1}{x ^{\frac{5}{3}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{2}{9} \frac{d}{d x} (x^{- \frac{5}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{9} (- \frac{5}{3} x^{- \frac{5}{3} - 1})

Simplify

\frac{2}{9} (- \frac{5}{3} x^{- \frac{5}{3} - 1}) : - \frac{10}{27 x ^{\frac{8}{3}}}

= - \frac{10}{27 x ^{\frac{8}{3}}}

y^{2} = x + 6, y^{2} = 2 - x

\frac{d}{d x} (4 cos (3 x))

\int_{1}^{2} tan (x y) d y

\frac{d}{d x} (8 x^{4} + 5 x^{3} - x^{2} + 4 x - 1)

- 7 (t - 4)

What is the derivative of 2/(9x^{5/3}) ?
The derivative of 2/(9x^{5/3}) is -(10)/(27x^{8/3)}
What is the first derivative of 2/(9x^{5/3}) ?
The first derivative of 2/(9x^{5/3}) is -(10)/(27x^{8/3)}