What is (\partial)/(\partial y)(4y^3-100y) ?

The answer to (\partial)/(\partial y)(4y^3-100y) is 12y^2-100

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(\partial)/(\partial y)(4y^3-100y)

\frac{\partial}{\partial y} (4 y^{3} - 100 y)

12 y^{2} - 100

Solution steps

\frac{\partial}{\partial y} (4 y^{3} - 100 y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 y^{3}) - \frac{\partial}{\partial y} (100 y)

\frac{\partial}{\partial y} (4 y^{3}) = 12 y^{2}

\frac{\partial}{\partial y} (100 y) = 100

= 12 y^{2} - 100

y^{^{'}} = (1 + x) (1 + y^{2})

\int e^{(- 2 x)} d x

\int_{- 1}^{2} (y + 2) - y^{2} d y

\int x y e^{x z} d z

What is (\partial)/(\partial y)(4y^3-100y) ?
The answer to (\partial)/(\partial y)(4y^3-100y) is 12y^2-100