What is (\partial)/(\partial x)(x^2+2x+y^2) ?

The answer to (\partial)/(\partial x)(x^2+2x+y^2) is 2x+2

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(\partial)/(\partial x)(x^2+2x+y^2)

\frac{\partial}{\partial x} (x^{2} + 2 x + y^{2})

2 x + 2

Solution steps

\frac{\partial}{\partial x} (x^{2} + 2 x + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 x + 2 + 0

Simplify

= 2 x + 2

f (x) = 4 x^{2} - x^{3}

\frac{\partial}{\partial z} (\frac{x}{y + 2 z})

x^{^{''}} + 4 x = 0

n = 1 \sum \infty \frac{1}{n + 1 ^{- n}}

5 y^{^{''}} + 15 y^{^{'}} - 20 y = 0

What is (\partial)/(\partial x)(x^2+2x+y^2) ?
The answer to (\partial)/(\partial x)(x^2+2x+y^2) is 2x+2