What is the derivative of f(x)=(1/4 x)^3 ?

The derivative of f(x)=(1/4 x)^3 is (3x^2)/(64)

What is the first derivative of f(x)=(1/4 x)^3 ?

The first derivative of f(x)=(1/4 x)^3 is (3x^2)/(64)

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derivative of

f (x) = (\frac{1}{4} x)^{3}

\frac{3 x ^{2}}{64}

Solution steps

\frac{d}{d x} ((\frac{1}{4} x)^{3})

Apply the chain rule:

3 (\frac{1}{4} x)^{2} \frac{d}{d x} (\frac{1}{4} x)

= 3 (\frac{1}{4} x)^{2} \frac{d}{d x} (\frac{1}{4} x)

\frac{d}{d x} (\frac{1}{4} x) = \frac{1}{4}

= 3 (\frac{1}{4} x)^{2} \frac{1}{4}

Simplify

3 (\frac{1}{4} x)^{2} \frac{1}{4} : \frac{3 x ^{2}}{64}

= \frac{3 x ^{2}}{64}

\frac{d}{d x} ((tan (x))^{2})

y^{^{'}} = - y - 2 x, y (0) = 1

\frac{d y}{d x} + 4 x y^{3} = 0

f (x) = (- 16 x^{2} + 36)^{2}

\frac{d}{d x} (arctan (tanh (x)))

What is the derivative of f(x)=(1/4 x)^3 ?
The derivative of f(x)=(1/4 x)^3 is (3x^2)/(64)
What is the first derivative of f(x)=(1/4 x)^3 ?
The first derivative of f(x)=(1/4 x)^3 is (3x^2)/(64)