What is the derivative of f(x)= x/(x^2-4) ?

The derivative of f(x)= x/(x^2-4) is (-x^2-4)/((x^2-4)^2)

What is the first derivative of f(x)= x/(x^2-4) ?

The first derivative of f(x)= x/(x^2-4) is (-x^2-4)/((x^2-4)^2)

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derivative of

f (x) = \frac{x}{x ^{2} - 4}

\frac{- x ^{2} - 4}{( x ^{2} - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{x ^{2} - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( x ^{2} - 4 ) - \frac{d}{d x} ( x ^{2} - 4 ) x}{( x ^{2} - 4 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} - 4) = 2 x

= \frac{1 \cdot ( x ^{2} - 4 ) - 2 xx}{( x ^{2} - 4 ) ^{2}}

1 \cdot (x^{2} - 4) - 2 xx = - x^{2} - 4

= \frac{- x ^{2} - 4}{( x ^{2} - 4 ) ^{2}}

9 x^{2} y^{^{'}} = y^{^{'}} + 6 x e^{- y}

y^{^{'}} = y (x y^{5} + 1)

y = ∣ x ∣, y = x^{2} - 1

(cos (x))^{\frac{1}{x}}

x = y^{2} - 4 y, x = 0

What is the derivative of f(x)= x/(x^2-4) ?
The derivative of f(x)= x/(x^2-4) is (-x^2-4)/((x^2-4)^2)
What is the first derivative of f(x)= x/(x^2-4) ?
The first derivative of f(x)= x/(x^2-4) is (-x^2-4)/((x^2-4)^2)