en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=|x|,y=x^2-1

Solution

area

y = ∣ x ∣, y = x^{2} - 1

Solution

\frac{7 + 5 5}{6}

+1

Decimal Notation

3.03005 \dots

Solution steps

Apply the area formula:

\int_{\frac{- 1 - 5}{2}}^{\frac{1 + 5}{2}} ∣ x ∣ - (x^{2} - 1) d x

Solve

\int_{\frac{- 1 - 5}{2}}^{\frac{1 + 5}{2}} ∣ x ∣ - (x^{2} - 1) d x : \frac{7 + 5 5}{6}

The area is:

= \frac{7 + 5 5}{6}

Popular Examples

taylor (cos(sqrt(x)))^{1/x}taylor

(cos (x))^{\frac{1}{x}}

area x=y^2-4y,x=0 area

x = y^{2} - 4 y, x = 0

y^'+(tan(t))y=tan(t)

y^{^{'}} + (tan (t)) y = tan (t)

derivative of y=(x^2+3x)^2 derivative of

y = (x^{2} + 3 x)^{2}

derivative of coth(x)

\frac{d}{d x} (coth (x))

Frequently Asked Questions (FAQ)

What is area y=|x|,y=x^2-1 ?
The answer to area y=|x|,y=x^2-1 is (7+5sqrt(5))/6