What is the tangent of y= 1/x ,(2, 1/2) ?

The tangent of y= 1/x ,(2, 1/2) is y=-1/4 x+1

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tangent of y= 1/x ,(2, 1/2)

tangent of

y = \frac{1}{x}, (2, \frac{1}{2})

y = - \frac{1}{4} x + 1

Solution steps

Find the slope of

y = \frac{1}{x} : \frac{d y}{d x} = - \frac{1}{x ^{2}}

Compute the slope of

y = \frac{1}{x}

(2, \frac{1}{2}) : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(2, \frac{1}{2}) : y = - \frac{1}{4} x + 1

y = - \frac{1}{4} x + 1

\frac{\partial}{\partial x} (e^{s i n (x)})

\frac{d}{d x} (16 - x)

x \to 0 lim (\frac{cos ( x - 1 )}{x})

\frac{d}{d x} (x^{2} + 8 x - 5)

x^{\frac{11}{12}}

What is the tangent of y= 1/x ,(2, 1/2) ?
The tangent of y= 1/x ,(2, 1/2) is y=-1/4 x+1