What is inverse oflaplace 4s ?

The answer to inverse oflaplace 4s is 4\delta'(t)

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inverse oflaplace 4s

inverse laplace

4 s

4 δ' (t)

Solution steps

L^{- 1} {4 s}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 4 L^{- 1} {s}

L^{- 1} {s} : δ^{'} (t)

= 4 δ^{^{'}} (t)

f (x) = \frac{2}{x}, at x = - 9

\frac{d}{d x} ((x^{2} + 2 x) e^{x})

\int_{- 1}^{1} cos (nπ x) d x

x^{2} + 2 x y - y^{2} + x = 51, (5, 7)

(4.3) (4.6)

What is inverse oflaplace 4s ?
The answer to inverse oflaplace 4s is 4\delta'(t)