What is (\partial)/(\partial x)(y+ln(x)) ?

The answer to (\partial)/(\partial x)(y+ln(x)) is 1/x

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(\partial)/(\partial x)(y+ln(x))

\frac{\partial}{\partial x} (y + ln (x))

\frac{1}{x}

Solution steps

\frac{\partial}{\partial x} (y + ln (x))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (ln (x))

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

= 0 + \frac{1}{x}

Simplify

= \frac{1}{x}

\frac{d}{d x} (\frac{3 x ^{2} + 2}{4})

\frac{\partial}{\partial x} (8 x^{2} + 4 y)

\int (x^{5} + 2)^{2} d x

\int_{0}^{2} 9 e^{- 2 x} d x

n = k \sum \infty \frac{1}{2 ^{n}}

What is (\partial)/(\partial x)(y+ln(x)) ?
The answer to (\partial)/(\partial x)(y+ln(x)) is 1/x