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Popular >

4y^'-12x^2=0

Solution

4 y^{^{'}} - 12 x^{2} = 0

Solution

y = x^{3} + c_{1}

Solution steps

4 y^{'} (x) - 12 x^{2} = 0

Isolate

y^{'} (x) : y^{'} (x) = 3 x^{2}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 3 x^{2} d x

\int 3 x^{2} d x = x^{3} + c_{1}

y = x^{3} + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for 4y^'-12x^2=0 ?
The solution for 4y^'-12x^2=0 is y=x^3+c_{1}