What is the integral of (\sqrt[3]{x})^2 ?

The integral of (\sqrt[3]{x})^2 is 3/5 x^{5/3}+C

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integral of (\sqrt[3]{x})^2

\frac{3}{5} x^{\frac{5}{3}} + C

Solution steps

Apply Integration By Parts

\int \frac{2}{3} x^{\frac{2}{3}} d x = \frac{2}{5} x^{\frac{5}{3}}

Simplify

= \frac{3}{5} x^{\frac{5}{3}}

Add a constant to the solution

= \frac{3}{5} x^{\frac{5}{3}} + C

\frac{d y}{d x} - \frac{1}{x} y = e^{(\frac{y}{x})}

x \to π lim ((x - π) tan (\frac{x}{2}))

\frac{\partial}{\partial x} (x y + yz + zy)

n = 0 \sum \infty \frac{3 ^{n}}{5 ^{n}}

y = 6 sin (x), at x = \frac{π}{6}

What is the integral of (\sqrt[3]{x})^2 ?
The integral of (\sqrt[3]{x})^2 is 3/5 x^{5/3}+C