What is (\partial)/(\partial x)(10xe^{-x^2-y^2}) ?

The answer to (\partial)/(\partial x)(10xe^{-x^2-y^2}) is 10(e^{-x^2-y^2}-2e^{-x^2-y^2}x^2)

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(\partial)/(\partial x)(10xe^{-x^2-y^2})

\frac{\partial}{\partial x} (10 x e^{- x^{2} - y^{2}})

10 (e^{- x^{2} - y^{2}} - 2 e^{- x^{2} - y^{2}} x^{2})

Solution steps

\frac{\partial}{\partial x} (10 x e^{- x^{2} - y^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{\partial}{\partial x} (x e^{- x^{2} - y^{2}})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{- x^{2} - y^{2}}

= 10 (\frac{\partial}{\partial x} (x) e^{- x^{2} - y^{2}} + \frac{\partial}{\partial x} (e^{- x^{2} - y^{2}}) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (e^{- x^{2} - y^{2}}) = - 2 e^{- x^{2} - y^{2}} x

= 10 (1 \cdot e^{- x^{2} - y^{2}} + (- 2 e^{- x^{2} - y^{2}} x) x)

Simplify

10 (1 \cdot e^{- x^{2} - y^{2}} + (- 2 e^{- x^{2} - y^{2}} x) x) : 10 (e^{- x^{2} - y^{2}} - 2 e^{- x^{2} - y^{2}} x^{2})

= 10 (e^{- x^{2} - y^{2}} - 2 e^{- x^{2} - y^{2}} x^{2})

y = x^{3} - 16 x, y = 4 - x, 0, 2

θ cos (θ) sin (θ)

x^{2} \frac{d y}{d x} - y^{3} = x y

\frac{d}{d x} (\frac{x}{1 - x ^{2}})

\int \frac{x ^{2}}{x ^{3} - 3} d x

What is (\partial)/(\partial x)(10xe^{-x^2-y^2}) ?
The answer to (\partial)/(\partial x)(10xe^{-x^2-y^2}) is 10(e^{-x^2-y^2}-2e^{-x^2-y^2}x^2)