What is area y=x^3-16x,y=4-x,0,2 ?

The answer to area y=x^3-16x,y=4-x,0,2 is 34

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x^3-16x,y=4-x,0,2

area

y = x^{3} - 16 x, y = 4 - x, 0, 2

34

Solution steps

Apply the area formula:

\int_{0}^{2} x^{3} - 16 x - (4 - x) d x

Solve

\int_{0}^{2} x^{3} - 16 x - (4 - x) d x : 34

The area is:

= 34

θ cos (θ) sin (θ)

x^{2} \frac{d y}{d x} - y^{3} = x y

\frac{d}{d x} (\frac{x}{1 - x ^{2}})

\int \frac{x ^{2}}{x ^{3} - 3} d x

\int_{0}^{5} 0.2 x d x