What is the solution for x^2(dy)/(dx)-y^3=xy ?

The solution for x^2(dy)/(dx)-y^3=xy is y= x/(sqrt(-2x+c_{1))},y=-x/(sqrt(-2x+c_{1))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2(dy)/(dx)-y^3=xy

x^{2} \frac{d y}{d x} - y^{3} = x y

y = \frac{x}{- 2 x + c _{1}}, y = - \frac{x}{- 2 x + c _{1}}

Solution steps

x^{2} \frac{d y}{d x} - y^{3} = x y

Solve Bernoulli ODE:

y = \frac{x}{- 2 x + c _{1}}, y = - \frac{x}{- 2 x + c _{1}}

y = \frac{x}{- 2 x + c _{1}}, y = - \frac{x}{- 2 x + c _{1}}

\frac{d}{d x} (\frac{x}{1 - x ^{2}})

\int \frac{x ^{2}}{x ^{3} - 3} d x

\int_{0}^{5} 0.2 x d x

n = 1 \sum \infty n (n + 1)

x \to 3 lim (x^{2} - 3 x)

What is the solution for x^2(dy)/(dx)-y^3=xy ?
The solution for x^2(dy)/(dx)-y^3=xy is y= x/(sqrt(-2x+c_{1))},y=-x/(sqrt(-2x+c_{1))}