What is the derivative of sqrt(2x^2-5x+4) ?

The derivative of sqrt(2x^2-5x+4) is (4x-5)/(2sqrt(2x^2-5x+4))

What is the first derivative of sqrt(2x^2-5x+4) ?

The first derivative of sqrt(2x^2-5x+4) is (4x-5)/(2sqrt(2x^2-5x+4))

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Popular >

\frac{d}{d x} (2 x^{2} - 5 x + 4)

\frac{4 x - 5}{2 2 x ^{2} - 5 x + 4}

Solution steps

\frac{d}{d x} (2 x^{2} - 5 x + 4)

Apply the chain rule:

\frac{1}{2 2 x ^{2} - 5 x + 4} \frac{d}{d x} (2 x^{2} - 5 x + 4)

= \frac{1}{2 2 x ^{2} - 5 x + 4} \frac{d}{d x} (2 x^{2} - 5 x + 4)

\frac{d}{d x} (2 x^{2} - 5 x + 4) = 4 x - 5

= \frac{1}{2 2 x ^{2} - 5 x + 4} (4 x - 5)

Simplify

\frac{1}{2 2 x ^{2} - 5 x + 4} (4 x - 5) : \frac{4 x - 5}{2 2 x ^{2} - 5 x + 4}

= \frac{4 x - 5}{2 2 x ^{2} - 5 x + 4}

100

\int (x - 4)^{2} x^{2} d x

\frac{\partial}{\partial x} (- 3 sin (2 x))

\frac{d}{d x} (2 a sin (x))

y^{^{'}} + 4 y = e^{- x}

What is the derivative of sqrt(2x^2-5x+4) ?
The derivative of sqrt(2x^2-5x+4) is (4x-5)/(2sqrt(2x^2-5x+4))
What is the first derivative of sqrt(2x^2-5x+4) ?
The first derivative of sqrt(2x^2-5x+4) is (4x-5)/(2sqrt(2x^2-5x+4))