What is the limit as x approaches 4 of (7x-1)/(x-4) ?

The limit as x approaches 4 of (7x-1)/(x-4) is diverges

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limit as x approaches 4 of (7x-1)/(x-4)

x \to 4 lim (\frac{7 x - 1}{x - 4})

diverges

Solution steps

x \to 4 lim (\frac{7 x - 1}{x - 4})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (\frac{7 x - 1}{x - 4}) = \infty

x \to 4 - lim (\frac{7 x - 1}{x - 4}) = - \infty

= diverges

\frac{d}{d x} (3 e^{4 x^{2}})

\frac{s}{( s ^{2} + 9 ) \cdot ( s ^{2} + 16 )}

ln (\frac{1 + x}{1 - x})

\frac{\partial}{\partial y} (4 x^{3} y^{3} - 2)

f (x) = \frac{4 + cot ( x )}{7 - tan ( x )}

What is the limit as x approaches 4 of (7x-1)/(x-4) ?
The limit as x approaches 4 of (7x-1)/(x-4) is diverges