What is the derivative of 3x^2-4x+3 ?

The derivative of 3x^2-4x+3 is 6x-4

What is the first derivative of 3x^2-4x+3 ?

The first derivative of 3x^2-4x+3 is 6x-4

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\frac{d}{d x} (3 x^{2} - 4 x + 3)

6 x - 4

Solution steps

\frac{d}{d x} (3 x^{2} - 4 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (3)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 6 x - 4 + 0

Simplify

= 6 x - 4

\frac{d}{d x} (\frac{1}{6 + x ^{2}})

y = \frac{e ^{x}}{x}

f (x) = x^{4} - 17 x^{2} + 16, at x = 2

- x^{2} + 10, - 10, - 1

\int \frac{1}{sin ^{2} ( x ) \cdot cos ^{2} ( x )} d x

What is the derivative of 3x^2-4x+3 ?
The derivative of 3x^2-4x+3 is 6x-4
What is the first derivative of 3x^2-4x+3 ?
The first derivative of 3x^2-4x+3 is 6x-4