What is the derivative of y=(e^x)/x ?

The derivative of y=(e^x)/x is (e^xx-e^x)/(x^2)

What is the first derivative of y=(e^x)/x ?

The first derivative of y=(e^x)/x is (e^xx-e^x)/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = \frac{e ^{x}}{x}

\frac{e ^{x} x - e ^{x}}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} ) x - \frac{d x}{d x} e ^{x}}{x ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d x}{d x} = 1

= \frac{e ^{x} x - 1 \cdot e ^{x}}{x ^{2}}

Simplify

= \frac{e ^{x} x - e ^{x}}{x ^{2}}

f (x) = x^{4} - 17 x^{2} + 16, at x = 2

- x^{2} + 10, - 10, - 1

\int \frac{1}{sin ^{2} ( x ) \cdot cos ^{2} ( x )} d x

y^{^{''}} + 6 y^{^{'}} + 9 y = \frac{e ^{- 3 x}}{x}

What is the derivative of y=(e^x)/x ?
The derivative of y=(e^x)/x is (e^xx-e^x)/(x^2)
What is the first derivative of y=(e^x)/x ?
The first derivative of y=(e^x)/x is (e^xx-e^x)/(x^2)