What is the integral from 3 to 8 of sqrt(1+x) ?

The integral from 3 to 8 of sqrt(1+x) is 38/3

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integral from 3 to 8 of sqrt(1+x)

\int_{3}^{8} 1 + x d x

\frac{38}{3}

Decimal Notation

12.66666 \dots

Solution steps

\int_{3}^{8} 1 + x d x

Apply u-substitution

: \int_{4}^{9} u d u

= \int_{4}^{9} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{9}

= [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{9}

Compute the boundaries:

\frac{38}{3}

= \frac{38}{3}

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What is the integral from 3 to 8 of sqrt(1+x) ?
The integral from 3 to 8 of sqrt(1+x) is 38/3