What is the derivative of (2x^2)/(6x+5) ?

The derivative of (2x^2)/(6x+5) is (2(6x^2+10x))/((6x+5)^2)

What is the first derivative of (2x^2)/(6x+5) ?

The first derivative of (2x^2)/(6x+5) is (2(6x^2+10x))/((6x+5)^2)

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derivative of

\frac{2 x ^{2}}{6 x + 5}

\frac{2 ( 6 x ^{2} + 10 x )}{( 6 x + 5 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x ^{2}}{6 x + 5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x ^{2}}{6 x + 5})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d}{d x} ( x ^{2} ) ( 6 x + 5 ) - \frac{d}{d x} ( 6 x + 5 ) x ^{2}}{( 6 x + 5 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x + 5) = 6

= 2 \cdot \frac{2 x ( 6 x + 5 ) - 6 x ^{2}}{( 6 x + 5 ) ^{2}}

Simplify

2 \cdot \frac{2 x ( 6 x + 5 ) - 6 x ^{2}}{( 6 x + 5 ) ^{2}} : \frac{2 ( 6 x ^{2} + 10 x )}{( 6 x + 5 ) ^{2}}

= \frac{2 ( 6 x ^{2} + 10 x )}{( 6 x + 5 ) ^{2}}

\int_{0}^{l n (2)} e^{3 x} d x

\frac{d}{d x} (\frac{x}{y})

\int \frac{4}{x ( x + 6 )} d x

y^{^{'}} = \frac{x ^{2} + y ^{2}}{x y}, y (1) = 1

n = 1 \sum \infty 8 (\frac{3}{4})^{n}

What is the derivative of (2x^2)/(6x+5) ?
The derivative of (2x^2)/(6x+5) is (2(6x^2+10x))/((6x+5)^2)
What is the first derivative of (2x^2)/(6x+5) ?
The first derivative of (2x^2)/(6x+5) is (2(6x^2+10x))/((6x+5)^2)