What is the integral from 0 to ln(2) of e^{3x} ?

The integral from 0 to ln(2) of e^{3x} is 7/3

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integral from 0 to ln(2) of e^{3x}

\int_{0}^{l n (2)} e^{3 x} d x

\frac{7}{3}

Decimal Notation

2.33333 \dots

Solution steps

\int_{0}^{l n (2)} e^{3 x} d x

Apply u-substitution

: \int_{0}^{3 l n (2)} e^{u} \frac{1}{3} d u

= \int_{0}^{3 l n (2)} e^{u} \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{0}^{3 l n (2)} e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{3} [e^{u}]_{0}^{3 l n (2)}

Compute the boundaries:

7

= \frac{1}{3} \cdot 7

Simplify

= \frac{7}{3}

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What is the integral from 0 to ln(2) of e^{3x} ?
The integral from 0 to ln(2) of e^{3x} is 7/3