What is the tangent of 2x^2-7x+5,\at x=2 ?

The tangent of 2x^2-7x+5,\at x=2 is y=x-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 2x^2-7x+5,\at x=2

tangent of

2 x^{2} - 7 x + 5, at x = 2

y = x - 3

Solution steps

Find the tangent point:

(2, - 1)

Find the slope of

y = 2 x^{2} - 7 x + 5 : \frac{d y}{d x} = 4 x - 7

Compute the slope of

y = 2 x^{2} - 7 x + 5

x = 2 : m = 1

Find the line with slope m=

1

and passing through

(2, - 1) : y = x - 3

y = x - 3

f (x) = x^{2} - 3 x + 5

x \to 0 + lim (e^{- \frac{2}{x ^{3}}})

x, 9

f (x) = \frac{5}{x - 4}, at x = 3

\int t^{2} - 5 t + 4 d t

What is the tangent of 2x^2-7x+5,\at x=2 ?
The tangent of 2x^2-7x+5,\at x=2 is y=x-3