What is (\partial)/(\partial x)(xcos(y)-ye^x) ?

The answer to (\partial)/(\partial x)(xcos(y)-ye^x) is cos(y)-ye^x

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(\partial)/(\partial x)(xcos(y)-ye^x)

\frac{\partial}{\partial x} (x cos (y) - y e^{x})

cos (y) - y e^{x}

Solution steps

\frac{\partial}{\partial x} (x cos (y) - y e^{x})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x cos (y)) - \frac{\partial}{\partial x} (y e^{x})

\frac{\partial}{\partial x} (x cos (y)) = cos (y)

\frac{\partial}{\partial x} (y e^{x}) = y e^{x}

= cos (y) - y e^{x}

n = 1 \sum \infty \frac{5}{n}

\int e x^{2} d x

e^{\frac{t}{9}} cos (\frac{t}{9})

\int \frac{8 x + 1}{x ^{2} + 1} d x

f (x) = \frac{8}{x}, at x = 5

What is (\partial)/(\partial x)(xcos(y)-ye^x) ?
The answer to (\partial)/(\partial x)(xcos(y)-ye^x) is cos(y)-ye^x