What is the tangent of f(x)=(3x-5)(x+4),(2,6) ?

The tangent of f(x)=(3x-5)(x+4),(2,6) is y=19x-32

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tangent of f(x)=(3x-5)(x+4),(2,6)

tangent of

f (x) = (3 x - 5) (x + 4), (2, 6)

y = 19 x - 32

Solution steps

Find the slope of

f (x) = (3 x - 5) (x + 4) : \frac{df ( x )}{d x} = 6 x + 7

Compute the slope of

f (x) = (3 x - 5) (x + 4)

(2, 6) : m = 19

Find the line with slope m=

19

and passing through

(2, 6) : y = 19 x - 32

y = 19 x - 32

\int_{3}^{\infty} \frac{x}{x ^{2} + 1} d x

x \to - 3 lim (\frac{5 x ^{2}}{x + 3})

\frac{\partial}{\partial y} (x + y^{2})

\int 6 x \cdot csc^{2} (8 x^{2}) d x

x \to 0 + lim (e^{\frac{- 1}{x}})

What is the tangent of f(x)=(3x-5)(x+4),(2,6) ?
The tangent of f(x)=(3x-5)(x+4),(2,6) is y=19x-32