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Popular >

xy+y^'=2x

Solution

x y + y^{^{'}} = 2 x

Solution

y = e^{- \frac{x ^{2}}{2} + c_{1}} + 2

Solution steps

x y + y^{'} (x) = 2 x

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} + c_{1}} + 2

y = e^{- \frac{x ^{2}}{2} + c_{1}} + 2

Popular Examples

f^'(x)=(x^2+3)/(cos(x))

f^{^{'}} (x) = \frac{x ^{2} + 3}{cos ( x )}

derivative of (10/3)t^2 derivative of

(\frac{10}{3}) t^{2}

d/(dn)((1+i)^nln(1+i)+(1-i)^nln(1-i))

\frac{d}{d n} ((1 + i)^{n} ln (1 + i) + (1 - i)^{n} ln (1 - i))

limit as x approaches 5+of-3/2 x+7/2

x \to 5 + lim (- \frac{3}{2} x + \frac{7}{2})

derivative of f(x)= 1/6 x^4-6x^2+1 derivative of

f (x) = \frac{1}{6} x^{4} - 6 x^{2} + 1

Frequently Asked Questions (FAQ)

What is the solution for xy+y^'=2x ?
The solution for xy+y^'=2x is y=e^{-(x^2)/2+c_{1}}+2