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Popular >

xydx+(x^2+y^2)dy=0

Solution

x y d x + (x^{2} + y^{2}) d y = 0

Solution

y = - x^{2} + x^{4} + c_{1}, y = - - x^{2} + x^{4} + c_{1}, y = - \frac{x ^{2} + x ^{4} + c _{1}}{x ^{2}} x, y = - - \frac{x ^{2} + x ^{4} + c _{1}}{x ^{2}} x

Solution steps

x y d x + (x^{2} + y^{2}) d y = 0

Solve using substitution:

y = - x^{2} + x^{4} + c_{1}, y = - - x^{2} + x^{4} + c_{1}, y = - \frac{x ^{2} + x ^{4} + c _{1}}{x ^{2}} x, y = - - \frac{x ^{2} + x ^{4} + c _{1}}{x ^{2}} x

y = - x^{2} + x^{4} + c_{1}, y = - - x^{2} + x^{4} + c_{1}, y = - \frac{x ^{2} + x ^{4} + c _{1}}{x ^{2}} x, y = - - \frac{x ^{2} + x ^{4} + c _{1}}{x ^{2}} x

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\int \frac{1}{( x - 5 ) ln ( x - 5 )} d x

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\int 7 e^{4 x} d x

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\int_{2}^{\infty} e^{- 3 x} d x

slope of (2,5),(8,-4)slope

(2, 5), (8, - 4)

d/(dt)(7/(sqrt(t)))

\frac{d}{d t} (\frac{7}{t})

Frequently Asked Questions (FAQ)

What is the solution for xydx+(x^2+y^2)dy=0 ?
The solution for xydx+(x^2+y^2)dy=0 is