What is the derivative of x^2+(432/x) ?

The derivative of x^2+(432/x) is 2x-(432)/(x^2)

What is the first derivative of x^2+(432/x) ?

The first derivative of x^2+(432/x) is 2x-(432)/(x^2)

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\frac{d}{d x} (x^{2} + \frac{432}{x})

2 x - \frac{432}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{2} + \frac{432}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (\frac{432}{x})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{432}{x}) = - \frac{432}{x ^{2}}

= 2 x - \frac{432}{x ^{2}}

\int \frac{1}{3 + x} d x

f (x) = ln (6 x^{3} + e^{x})

\frac{d}{d x} (\frac{1}{( x ^{2} - 3 x ) ^{2}})

y^{^{'}} = \frac{y - x}{x}

\frac{\partial}{\partial x} (4 x^{5} y)

What is the derivative of x^2+(432/x) ?
The derivative of x^2+(432/x) is 2x-(432)/(x^2)
What is the first derivative of x^2+(432/x) ?
The first derivative of x^2+(432/x) is 2x-(432)/(x^2)