What is the derivative of 1/((x^2-3x^2)) ?

The derivative of 1/((x^2-3x^2)) is -(2(2x-3))/((x^2-3x)^3)

What is the first derivative of 1/((x^2-3x^2)) ?

The first derivative of 1/((x^2-3x^2)) is -(2(2x-3))/((x^2-3x)^3)

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\frac{d}{d x} (\frac{1}{( x ^{2} - 3 x ) ^{2}})

- \frac{2 ( 2 x - 3 )}{( x ^{2} - 3 x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{( x ^{2} - 3 x ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x^{2} - 3 x)^{- 2})

Apply the chain rule:

- \frac{2}{( x ^{2} - 3 x ) ^{3}} \frac{d}{d x} (x^{2} - 3 x)

= - \frac{2}{( x ^{2} - 3 x ) ^{3}} \frac{d}{d x} (x^{2} - 3 x)

\frac{d}{d x} (x^{2} - 3 x) = 2 x - 3

= - \frac{2}{( x ^{2} - 3 x ) ^{3}} (2 x - 3)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{2 ( 2 x - 3 )}{( x ^{2} - 3 x ) ^{3}}

y^{^{'}} = \frac{y - x}{x}

\frac{\partial}{\partial x} (4 x^{5} y)

\frac{\partial}{\partial x} (\frac{x ^{2} - 1}{x ^{2} + x + 1})

\int 2^{r} d r

f (x) = 3 + x

What is the derivative of 1/((x^2-3x^2)) ?
The derivative of 1/((x^2-3x^2)) is -(2(2x-3))/((x^2-3x)^3)
What is the first derivative of 1/((x^2-3x^2)) ?
The first derivative of 1/((x^2-3x^2)) is -(2(2x-3))/((x^2-3x)^3)