What is the tangent of f(x)= 1/6 x^4,\at x=-1 ?

The tangent of f(x)= 1/6 x^4,\at x=-1 is y=-2/3 x-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 1/6 x^4,\at x=-1

tangent of

f (x) = \frac{1}{6} x^{4}, at x = - 1

y = - \frac{2}{3} x - \frac{1}{2}

Solution steps

Find the tangent point:

(- 1, \frac{1}{6})

Find the slope of

f (x) = \frac{1}{6} x^{4} : \frac{df ( x )}{d x} = \frac{2 x ^{3}}{3}

Compute the slope of

f (x) = \frac{1}{6} x^{4}

x = - 1 : m = - \frac{2}{3}

Find the line with slope m=

- \frac{2}{3}

and passing through

(- 1, \frac{1}{6}) : y = - \frac{2}{3} x - \frac{1}{2}

y = - \frac{2}{3} x - \frac{1}{2}

1 - e^{- t} sin (2 t)

\frac{d}{d x} (8 x (x^{2} + 3)^{3})

f (x) = 16 - x^{2}

(4 x)^{^{'}}

\int (5 x^{2} + 5 x + 3)^{4} (2 x + 1) d x

What is the tangent of f(x)= 1/6 x^4,\at x=-1 ?
The tangent of f(x)= 1/6 x^4,\at x=-1 is y=-2/3 x-1/2