What is the solution for (dy)/(dt)(t)+2y=3e^{-t} ?

The solution for (dy)/(dt)(t)+2y=3e^{-t} is y=(3(-e^{-t}t-e^{-t}))/(t^2)+(c_{1})/(t^2)

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(dy)/(dt)(t)+2y=3e^{-t}

\frac{d y}{d t} (t) + 2 y = 3 e^{- t}

y = \frac{3 ( - e ^{- t} t - e ^{- t} )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

Solution steps

\frac{d y}{d t} (t) + 2 y = 3 e^{- t}

Solve linear ODE:

y = \frac{3 ( - e ^{- t} t - e ^{- t} )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

y = \frac{3 ( - e ^{- t} t - e ^{- t} )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

\frac{\partial}{\partial x} (cos (2 x + y))

\frac{d}{d x} (3 x^{2} + 8 x)

x \to 1 lim (\frac{x + 6}{x + 1})

x \to 1 lim (arctan (ln (x)))

\frac{d}{d x} (4 x^{3} - 5 x^{2} + ln (x))

What is the solution for (dy)/(dt)(t)+2y=3e^{-t} ?
The solution for (dy)/(dt)(t)+2y=3e^{-t} is y=(3(-e^{-t}t-e^{-t}))/(t^2)+(c_{1})/(t^2)