What is the integral of sin(5x)cos(3x) ?

The integral of sin(5x)cos(3x) is 1/2 (-1/8 cos(8x)-1/2 cos(2x))+C

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integral of sin(5x)cos(3x)

\int sin (5 x) cos (3 x) d x

\frac{1}{2} (- \frac{1}{8} cos (8 x) - \frac{1}{2} cos (2 x)) + C

Solution steps

\int sin (5 x) cos (3 x) d x

Use the following identity:

cos (t) sin (s) = \frac{sin ( s + t ) + sin ( s - t )}{2}

= \int \frac{sin ( 5 x + 3 x ) + sin ( 5 x - 3 x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sin (5 x + 3 x) + sin (5 x - 3 x) d x

Simplify

= \frac{1}{2} \cdot \int sin (8 x) + sin (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int sin (8 x) d x + \int sin (2 x) d x)

\int sin (8 x) d x = - \frac{1}{8} cos (8 x)

\int sin (2 x) d x = - \frac{1}{2} cos (2 x)

= \frac{1}{2} (- \frac{1}{8} cos (8 x) - \frac{1}{2} cos (2 x))

Add a constant to the solution

= \frac{1}{2} (- \frac{1}{8} cos (8 x) - \frac{1}{2} cos (2 x)) + C

n = 1 \sum \infty \frac{3 n}{n ^{2} + 2}

\int_{0}^{2 π} 1

\int_{- \infty}^{0} 9^{x} d x

\int 5 m (12 m^{3} - 10 m) d m

2 x^{2} + 10 x - \frac{4}{x ^{2}}, at x = - 5

What is the integral of sin(5x)cos(3x) ?
The integral of sin(5x)cos(3x) is 1/2 (-1/8 cos(8x)-1/2 cos(2x))+C