What is the derivative of y=(t^2-7)^2 ?

The derivative of y=(t^2-7)^2 is 4t(t^2-7)

What is the first derivative of y=(t^2-7)^2 ?

The first derivative of y=(t^2-7)^2 is 4t(t^2-7)

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derivative of

y = (t^{2} - 7)^{2}

4 t (t^{2} - 7)

Solution steps

\frac{d}{d t} ((t^{2} - 7)^{2})

Apply the chain rule:

2 (t^{2} - 7) \frac{d}{d t} (t^{2} - 7)

= 2 (t^{2} - 7) \frac{d}{d t} (t^{2} - 7)

\frac{d}{d t} (t^{2} - 7) = 2 t

= 2 (t^{2} - 7) \cdot 2 t

Simplify

= 4 t (t^{2} - 7)

\frac{\partial}{\partial x} (4 cos (x))

\frac{d}{d x} (8 arcsin (x^{4}))

\frac{\partial}{\partial x} (4 x^{2} + 4 y^{2})

y^{^{'}} + 5 y = x

\frac{d}{d x} (x^{3} - 3 x^{2} + 3)

What is the derivative of y=(t^2-7)^2 ?
The derivative of y=(t^2-7)^2 is 4t(t^2-7)
What is the first derivative of y=(t^2-7)^2 ?
The first derivative of y=(t^2-7)^2 is 4t(t^2-7)