What is (\partial)/(\partial x)(4cos(x)) ?

The answer to (\partial)/(\partial x)(4cos(x)) is -4sin(x)

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(\partial)/(\partial x)(4cos(x))

\frac{\partial}{\partial x} (4 cos (x))

- 4 sin (x)

Solution steps

\frac{\partial}{\partial x} (4 cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 4 (- sin (x))

Simplify

= - 4 sin (x)

\frac{d}{d x} (8 arcsin (x^{4}))

\frac{\partial}{\partial x} (4 x^{2} + 4 y^{2})

y^{^{'}} + 5 y = x

\frac{d}{d x} (x^{3} - 3 x^{2} + 3)

\frac{d}{d x} (e^{x} - x^{3} - 7)

What is (\partial)/(\partial x)(4cos(x)) ?
The answer to (\partial)/(\partial x)(4cos(x)) is -4sin(x)