What is the first (5sin(x))^' ?

The first (5sin(x))^' is 5cos(x)

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(5sin(x))^'

(5 sin (x))^{^{'}}

5 cos (x)

Solution steps

(5 sin (x))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 (sin (x))^{^{'}}

Apply the common derivative:

(sin (x))^{'} = cos (x)

= 5 cos (x)

\int_{1}^{4} 1 + \frac{9 x}{4} d x

\frac{\partial}{\partial y} (5 x^{2} y + 5 x y^{2})

\frac{d}{d x} (x (x - 1)^{2})

y^{^{'}} = \frac{( 1 + y )}{x ^{2} + x}

\frac{1}{3 s}