What is the derivative of x(x-1^2) ?

The derivative of x(x-1^2) is 3x^2-4x+1

What is the first derivative of x(x-1^2) ?

The first derivative of x(x-1^2) is 3x^2-4x+1

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\frac{d}{d x} (x (x - 1)^{2})

3 x^{2} - 4 x + 1

Solution steps

\frac{d}{d x} (x (x - 1)^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = (x - 1)^{2}

= \frac{d x}{d x} (x - 1)^{2} + \frac{d}{d x} ((x - 1)^{2}) x

\frac{d x}{d x} = 1

\frac{d}{d x} ((x - 1)^{2}) = 2 (x - 1)

= 1 \cdot (x - 1)^{2} + 2 (x - 1) x

Simplify

1 \cdot (x - 1)^{2} + 2 (x - 1) x : 3 x^{2} - 4 x + 1

= 3 x^{2} - 4 x + 1

y^{^{'}} = \frac{( 1 + y )}{x ^{2} + x}

\frac{1}{3 s}

\frac{\partial}{\partial x} (x^{2} y z^{2})

\frac{\partial}{\partial y} (2 x ln (y) - yz)

(e^{- x} - e^{5}) (e^{x} + e^{- 2})

What is the derivative of x(x-1^2) ?
The derivative of x(x-1^2) is 3x^2-4x+1
What is the first derivative of x(x-1^2) ?
The first derivative of x(x-1^2) is 3x^2-4x+1