What is (\partial)/(\partial x)(cos(x)cosh(y)) ?

The answer to (\partial)/(\partial x)(cos(x)cosh(y)) is -sin(x)cosh(y)

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(\partial)/(\partial x)(cos(x)cosh(y))

\frac{\partial}{\partial x} (cos (x) cosh (y))

- sin (x) cosh (y)

Solution steps

\frac{\partial}{\partial x} (cos (x) cosh (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cosh (y) \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= cosh (y) (- sin (x))

Simplify

= - sin (x) cosh (y)

x^{4} e^{x} - 5

\int 3 x^{2} \times 4 x^{4} d x

\int 5 x^{3} e^{- x^{2}} d x

\int \frac{1}{16 x ^{2} - 9} d x

\frac{4 x + 3}{4 x - 3}

What is (\partial)/(\partial x)(cos(x)cosh(y)) ?
The answer to (\partial)/(\partial x)(cos(x)cosh(y)) is -sin(x)cosh(y)