What is the derivative of y(θ)= pi/8 sin(θ) ?

The derivative of y(θ)= pi/8 sin(θ) is pi/8 cos(θ)

What is the first derivative of y(θ)= pi/8 sin(θ) ?

The first derivative of y(θ)= pi/8 sin(θ) is pi/8 cos(θ)

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derivative of

y (θ) = \frac{π}{8} sin (θ)

\frac{π}{8} cos (θ)

Solution steps

\frac{d}{d θ} (\frac{π}{8} sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{π}{8} \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= \frac{π}{8} cos (θ)

\int \frac{1}{b ^{2} 25 + b ^{2}} d b

\frac{d}{d x} (2 - 4 cos (x))

y^{^{'}} = \frac{x y}{1 - x ^{2}}

f (x) = cos (x^{3})

\frac{2 x}{x ^{2} + y ^{2}}

What is the derivative of y(θ)= pi/8 sin(θ) ?
The derivative of y(θ)= pi/8 sin(θ) is pi/8 cos(θ)
What is the first derivative of y(θ)= pi/8 sin(θ) ?
The first derivative of y(θ)= pi/8 sin(θ) is pi/8 cos(θ)