What is the solution for 1/(x^2)dx=e^{-2t}dt ?

The solution for 1/(x^2)dx=e^{-2t}dt is x=-(2e^{2t})/(-1+2c_{1)e^{2t}}

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1/(x^2)dx=e^{-2t}dt

\frac{1}{x ^{2}} d x = e^{- 2 t} d t

x = - \frac{2 e ^{2 t}}{- 1 + 2 c _{1} e ^{2 t}}

Solution steps

\frac{1}{x ^{2}} d x = e^{- 2 t} d t

Solve separable ODE:

x = - \frac{2 e ^{2 t}}{- 1 + 2 c _{1} e ^{2 t}}

x = - \frac{2 e ^{2 t}}{- 1 + 2 c _{1} e ^{2 t}}

- x^{3} (- 1.1)

ln (1 + x^{2})

\frac{\partial}{\partial y} (6 y^{2} e^{6 x y})

\frac{d}{d x} (x^{4} - 12 x^{3} + 48 x^{2} - 64 x)

\int \frac{x - 1}{( 2 x + 5 ) ( x - 8 )} d x

What is the solution for 1/(x^2)dx=e^{-2t}dt ?
The solution for 1/(x^2)dx=e^{-2t}dt is x=-(2e^{2t})/(-1+2c_{1)e^{2t}}