What is the tangent of y=x^2+x,\at x=-2 ?

The tangent of y=x^2+x,\at x=-2 is y=-3x-4

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tangent of y=x^2+x,\at x=-2

tangent of

y = x^{2} + x, at x = - 2

y = - 3 x - 4

Solution steps

Find the tangent point:

(- 2, 2)

Find the slope of

y = x^{2} + x : \frac{d y}{d x} = 2 x + 1

Compute the slope of

y = x^{2} + x

x = - 2 : m = - 3

Find the line with slope m=

- 3

and passing through

(- 2, 2) : y = - 3 x - 4

y = - 3 x - 4

\int_{- \infty}^{0} \frac{1}{4 - 2 x} d x

\int_{0.5}^{t + 4} 3 d x

\int_{- 1}^{3} (4 - 2 x) d x

\int_{0}^{9} k (9 - x)

\frac{d}{d x} (arctan (\frac{a ^{2} - x ^{3}}{b ^{2}}))

What is the tangent of y=x^2+x,\at x=-2 ?
The tangent of y=x^2+x,\at x=-2 is y=-3x-4